What is the integral of (9sqrt(x^3)+7\sqrt[3]{x^2}) ?

The integral of (9sqrt(x^3)+7\sqrt[3]{x^2}) is 18/5 x^{5/2}+21/5 x^{5/3}+C

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integral of (9sqrt(x^3)+7\sqrt[3]{x^2})

\frac{18}{5} x^{\frac{5}{2}} + \frac{21}{5} x^{\frac{5}{3}} + C

Solution steps

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

\int 9 x^{3} d x = \frac{18}{5} x^{\frac{5}{2}}

= \frac{18}{5} x^{\frac{5}{2}} + \frac{21}{5} x^{\frac{5}{3}}

Add a constant to the solution

= \frac{18}{5} x^{\frac{5}{2}} + \frac{21}{5} x^{\frac{5}{3}} + C

y = x^{3} - 2 x + 1, (2, 5)

\int_{- 2}^{1} ∣ x ∣ d x

\frac{d y}{d x} + a y = b

\int \frac{x ^{3}}{( 7 - x ^{4} ) ^{5}} d x

\frac{\partial}{\partial x} (e^{x (e^{y})})

What is the integral of (9sqrt(x^3)+7\sqrt[3]{x^2}) ?
The integral of (9sqrt(x^3)+7\sqrt[3]{x^2}) is 18/5 x^{5/2}+21/5 x^{5/3}+C