What is the integral from 1 to 2x-1 of e^t ?

The integral from 1 to 2x-1 of e^t is e^{2x-1}-e

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integral from 1 to 2x-1 of e^t

\int_{1}^{2 x - 1} e^{t} d t

e^{2 x - 1} - e

Solution steps

\int_{1}^{2 x - 1} e^{t} d t

Use the common integral:

\int e^{t} d t = e^{t}

= [e^{t}]_{1}^{2 x - 1}

Compute the boundaries:

e^{2 x - 1} - e

= e^{2 x - 1} - e

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What is the integral from 1 to 2x-1 of e^t ?
The integral from 1 to 2x-1 of e^t is e^{2x-1}-e