What is the integral from 0 to 3/2 of |sin(x)| ?

The integral from 0 to 3/2 of |sin(x)| is -cos(3/2)+1

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integral from 0 to 3/2 of |sin(x)|

\int_{0}^{\frac{3}{2}} ∣ sin (x) ∣ d x

- cos (\frac{3}{2}) + 1

Decimal

0.92926 \dots

Solution steps

\int_{0}^{\frac{3}{2}} ∣ sin (x) ∣ d x

Eliminate Absolutes

= \int_{0}^{\frac{3}{2}} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{0}^{\frac{3}{2}}

Compute the boundaries:

- cos (\frac{3}{2}) + 1

= - cos (\frac{3}{2}) + 1

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What is the integral from 0 to 3/2 of |sin(x)| ?
The integral from 0 to 3/2 of |sin(x)| is -cos(3/2)+1