What is the integral from infinity to-1 of 1/(x^2) ?

The integral from infinity to-1 of 1/(x^2) is diverges

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integral from infinity to-1 of 1/(x^2)

\int_{\infty}^{- 1} \frac{1}{x ^{2}} d x

diverges

Solution steps

\int_{\infty}^{- 1} \frac{1}{x ^{2}} d x

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{- 1}^{\infty} \frac{1}{x ^{2}} d x

\int_{- 1}^{\infty} \frac{1}{x ^{2}} d x =

diverges

= diverges

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What is the integral from infinity to-1 of 1/(x^2) ?
The integral from infinity to-1 of 1/(x^2) is diverges