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Popular >

integral from-8 to 9 of (1-x)

Solution

\int_{- 8}^{9} (1 - x) d x

Solution

\frac{17}{2}

+1

Decimal

8.5

Solution steps

\int_{- 8}^{9} 1 - x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 8}^{9} 1 d x - \int_{- 8}^{9} x d x

\int_{- 8}^{9} 1 d x = 17

\int_{- 8}^{9} x d x = \frac{17}{2}

= 17 - \frac{17}{2}

Simplify

17 - \frac{17}{2} : \frac{17}{2}

= \frac{17}{2}

Graph

Popular Examples

integral from 0 to pi of sin^2(x)sin(x)

\int_{0}^{π} sin^{2} (x) sin (x) d x

integral from-pi to pi of sin(m)xsin(n)x

\int_{- π}^{π} sin (m) x sin (n) x d x

integral from 1 to 4 of (9/x-e^{-x})

\int_{1}^{4} (\frac{9}{x} - e^{- x}) d x

integral from 0 to 3 of 8-2x

\int_{0}^{3} 8 - 2 x d x

integral from 0 to 3 of (6x)/(1+x^2)

\int_{0}^{3} \frac{6 x}{1 + x ^{2}} d x

Frequently Asked Questions (FAQ)

What is the integral from-8 to 9 of (1-x) ?
The integral from-8 to 9 of (1-x) is 17/2