What is the integral from 1 to 16 of (x^{-7/4}) ?

The integral from 1 to 16 of (x^{-7/4}) is 7/6

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integral from 1 to 16 of (x^{-7/4})

\int_{1}^{16} (x^{- \frac{7}{4}}) d x

\frac{7}{6}

Decimal

1.16666 \dots

Solution steps

\int_{1}^{16} x^{- \frac{7}{4}} d x

Apply the Power Rule

: [- \frac{4}{3 x ^{\frac{3}{4}}}]_{1}^{16}

= [- \frac{4}{3 x ^{\frac{3}{4}}}]_{1}^{16}

Compute the boundaries:

\frac{7}{6}

= \frac{7}{6}

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What is the integral from 1 to 16 of (x^{-7/4}) ?
The integral from 1 to 16 of (x^{-7/4}) is 7/6