What is the integral from 0 to pi of 9-9cos^2(x) ?

The integral from 0 to pi of 9-9cos^2(x) is 9pi-(9pi)/2

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integral from 0 to pi of 9-9cos^2(x)

\int_{0}^{π} 9 - 9 cos^{2} (x) d x

9 π - \frac{9 π}{2}

Decimal

14.13716 \dots

Solution steps

\int_{0}^{π} 9 - 9 cos^{2} (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{π} 9 d x - \int_{0}^{π} 9 cos^{2} (x) d x

\int_{0}^{π} 9 d x = 9 π

\int_{0}^{π} 9 cos^{2} (x) d x = \frac{9 π}{2}

= 9 π - \frac{9 π}{2}

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What is the integral from 0 to pi of 9-9cos^2(x) ?
The integral from 0 to pi of 9-9cos^2(x) is 9pi-(9pi)/2