What is the integral from 0 to 1 of (5x^2-8x+6) ?

The integral from 0 to 1 of (5x^2-8x+6) is 11/3

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integral from 0 to 1 of (5x^2-8x+6)

\int_{0}^{1} (5 x^{2} - 8 x + 6) d x

\frac{11}{3}

Decimal

3.66666 \dots

Solution steps

\int_{0}^{1} 5 x^{2} - 8 x + 6 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 5 x^{2} d x - \int_{0}^{1} 8 x d x + \int_{0}^{1} 6 d x

\int_{0}^{1} 5 x^{2} d x = \frac{5}{3}

\int_{0}^{1} 8 x d x = 4

\int_{0}^{1} 6 d x = 6

= \frac{5}{3} - 4 + 6

Simplify

\frac{5}{3} - 4 + 6 : \frac{11}{3}

= \frac{11}{3}

\int_{1}^{2} k x d x

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\int_{0}^{1} e^{x} + x^{2} d x

\int_{- \infty}^{0} \frac{1}{e ^{x} + 1} d x

\int_{0}^{1 - x} x - x^{2} - x y d y

What is the integral from 0 to 1 of (5x^2-8x+6) ?
The integral from 0 to 1 of (5x^2-8x+6) is 11/3