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Popular >

integral from-1 to 2 of (x^3+1)

Solution

\int_{- 1}^{2} (x^{3} + 1) d x

Solution

\frac{27}{4}

+1

Decimal

6.75

Solution steps

\int_{- 1}^{2} x^{3} + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{2} x^{3} d x + \int_{- 1}^{2} 1 d x

\int_{- 1}^{2} x^{3} d x = \frac{15}{4}

\int_{- 1}^{2} 1 d x = 3

= \frac{15}{4} + 3

Simplify

\frac{15}{4} + 3 : \frac{27}{4}

= \frac{27}{4}

Graph

Popular Examples

integral from-1 to 2 of 8-x^2-x

\int_{- 1}^{2} 8 - x^{2} - x d x

integral from-2 to 2 of sqrt(1-(x^2)/4)

\int_{- 2}^{2} 1 - \frac{x ^{2}}{4} d x

integral from-2 to 1 of 2x^2

\int_{- 2}^{1} 2 x^{2} d x

integral from-1 to 1 of (x^2-x)(x+1)

\int_{- 1}^{1} (x^{2} - x) (x + 1) d x

integral from 3 to 5 of 80-(240)/(x+4)

\int_{3}^{5} 80 - \frac{240}{x + 4} d x

Frequently Asked Questions (FAQ)

What is the integral from-1 to 2 of (x^3+1) ?
The integral from-1 to 2 of (x^3+1) is 27/4