What is the integral from 0 to 200 of-0.04x+10 ?

The integral from 0 to 200 of-0.04x+10 is 1200

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integral from 0 to 200 of-0.04x+10

\int_{0}^{200} - 0.04 x + 10 d x

1200

Solution steps

\int_{0}^{200} - 0.04 x + 10 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{200} 0.04 x d x + \int_{0}^{200} 10 d x

\int_{0}^{200} 0.04 x d x = 800

\int_{0}^{200} 10 d x = 2000

= - 800 + 2000

Simplify

= 1200

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What is the integral from 0 to 200 of-0.04x+10 ?
The integral from 0 to 200 of-0.04x+10 is 1200