What is the derivative of y= 2/(x^3) ?

The derivative of y= 2/(x^3) is -6/(x^4)

What is the first derivative of y= 2/(x^3) ?

The first derivative of y= 2/(x^3) is -6/(x^4)

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derivative of

y = \frac{2}{x ^{3}}

- \frac{6}{x ^{4}}

Solution steps

\frac{d}{d x} (\frac{2}{x ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{1}{x ^{3}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 \frac{d}{d x} (x^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 (- 3 x^{- 3 - 1})

Simplify

2 (- 3 x^{- 3 - 1}) : - \frac{6}{x ^{4}}

= - \frac{6}{x ^{4}}

\frac{\partial}{\partial z} (x sin (y - z))

\int \frac{x ^{3}}{u} d x

x^{3} - 3 x^{2} + 3

\int_{0}^{17} x d x

cos^{2} (21 t)

What is the derivative of y= 2/(x^3) ?
The derivative of y= 2/(x^3) is -6/(x^4)
What is the first derivative of y= 2/(x^3) ?
The first derivative of y= 2/(x^3) is -6/(x^4)