en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 2 of-x+1

Solution

\int_{0}^{2} - x + 1 d x

Solution

0

Solution steps

\int_{0}^{2} - x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{2} x d x + \int_{0}^{2} 1 d x

\int_{0}^{2} x d x = 2

\int_{0}^{2} 1 d x = 2

= - 2 + 2

Simplify

= 0

Graph

Popular Examples

integral from-4 to 4 of |x^2+x-2|

\int_{- 4}^{4} x^{2} + x - 2 d x

integral from 0 to 1 of pi(1-x)

\int_{0}^{1} π (1 - x) d x

integral from x^3 to sqrt(x of)y

\int_{x^{3}}^{x} y d y

integral from-5 to 2 of (1-x)

\int_{- 5}^{2} (1 - x) d x

integral from 1 to 2 of ((3x^2+9x+1)/x)

\int_{1}^{2} (\frac{3 x ^{2} + 9 x + 1}{x}) d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 2 of-x+1 ?
The integral from 0 to 2 of-x+1 is 0