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Popular >

integral from-1 to 1 of (8-x)

Solution

\int_{- 1}^{1} (8 - x) d x

Solution

16

Solution steps

\int_{- 1}^{1} 8 - x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} 8 d x - \int_{- 1}^{1} x d x

\int_{- 1}^{1} 8 d x = 16

\int_{- 1}^{1} x d x = 0

= 16 - 0

Simplify

= 16

Graph

Popular Examples

integral from 0 to 1 of cos(t^2)

\int_{0}^{1} cos (t^{2}) d t

integral from-3 to 5 of 5/(x^5)

\int_{- 3}^{5} \frac{5}{x ^{5}} d x

integral from 0 to 1 of t*e^t

\int_{0}^{1} t \cdot e^{t} d t

integral from 0 to 8 of-6x^2-18x+528

\int_{0}^{8} - 6 x^{2} - 18 x + 528 d x

integral from 0 to 2pi of 1/x

\int_{0}^{2 π} \frac{1}{x} d x

Frequently Asked Questions (FAQ)

What is the integral from-1 to 1 of (8-x) ?
The integral from-1 to 1 of (8-x) is 16