What is the integral from 1 to 4 of k/x ?

The integral from 1 to 4 of k/x is k*2ln(2)

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integral from 1 to 4 of k/x

\int_{1}^{4} \frac{k}{x} d x

k \cdot 2 ln (2)

Solution steps

\int_{1}^{4} \frac{k}{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= k \cdot \int_{1}^{4} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= k [ln ∣ x ∣]_{1}^{4}

Compute the boundaries:

2 ln (2)

= k \cdot 2 ln (2)

\int_{1}^{3} \frac{1}{x ^{5}} d x

\int_{0}^{4 - y^{2} - z^{2}} 1 d x

\int_{5}^{7} \frac{1}{x - 2} d x

\int_{0}^{1} x^{3} - 1 d x

\int_{1}^{2} (\frac{x}{2} - \frac{6}{x}) d x

What is the integral from 1 to 4 of k/x ?
The integral from 1 to 4 of k/x is k*2ln(2)