What is the integral of (2x+1)/(x^2+x+1) ?

The integral of (2x+1)/(x^2+x+1) is ln|x^2+x+1|+C

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integral of (2x+1)/(x^2+x+1)

\int \frac{2 x + 1}{x ^{2} + x + 1} d x

ln x^{2} + x + 1 + C

Solution steps

\int \frac{2 x + 1}{x ^{2} + x + 1} d x

Apply u-substitution

: \int \frac{1}{u} d u

= \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= ln ∣ u ∣

Substitute back

u = x^{2} + x + 1

= ln x^{2} + x + 1

Add a constant to the solution

= ln x^{2} + x + 1 + C

x = - y - 5, x = 5 y - 11, y = 0

\int (sec^{2} (x) + 4) d x

\int \frac{( 1 - x )}{x} d x

\int (4 t^{2} + 3)^{2} d t

What is the integral of (2x+1)/(x^2+x+1) ?
The integral of (2x+1)/(x^2+x+1) is ln|x^2+x+1|+C