What is the integral from 0 to 1 of 25-(x-5)^2 ?

The integral from 0 to 1 of 25-(x-5)^2 is 14/3

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integral from 0 to 1 of 25-(x-5)^2

\int_{0}^{1} 25 - (x - 5)^{2} d x

\frac{14}{3}

Decimal

4.66666 \dots

Solution steps

\int_{0}^{1} 25 - (x - 5)^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 25 d x - \int_{0}^{1} (x - 5)^{2} d x

\int_{0}^{1} 25 d x = 25

\int_{0}^{1} (x - 5)^{2} d x = \frac{61}{3}

= 25 - \frac{61}{3}

Simplify

25 - \frac{61}{3} : \frac{14}{3}

= \frac{14}{3}

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What is the integral from 0 to 1 of 25-(x-5)^2 ?
The integral from 0 to 1 of 25-(x-5)^2 is 14/3