What is the integral from 0 to pi/4 of 3tan(x) ?

The integral from 0 to pi/4 of 3tan(x) is 3/2 ln(2)

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integral from 0 to pi/4 of 3tan(x)

\int_{0}^{\frac{π}{4}} 3 tan (x) d x

\frac{3}{2} ln (2)

Decimal

1.03972 \dots

Solution steps

\int_{0}^{\frac{π}{4}} 3 tan (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{0}^{\frac{π}{4}} tan (x) d x

Rewrite using trig identities

= 3 \cdot \int_{0}^{\frac{π}{4}} \frac{sin ( x )}{cos ( x )} d x

Apply u-substitution

: \int_{1}^{\frac{2}{2}} - \frac{1}{u} d u

= 3 \cdot \int_{1}^{\frac{2}{2}} - \frac{1}{u} d u

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= 3 (- \int_{\frac{2}{2}}^{1} - \frac{1}{u} d u)

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 (- (- \int_{\frac{2}{2}}^{1} \frac{1}{u} d u))

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= 3 (- (- [ln ∣ u ∣]_{\frac{2}{2}}^{1}))

Simplify

3 (- (- [ln ∣ u ∣]_{\frac{2}{2}}^{1})) : 3 [ln ∣ u ∣]_{\frac{1}{2}}^{1}

= 3 [ln ∣ u ∣]_{\frac{1}{2}}^{1}

Compute the boundaries:

\frac{1}{2} ln (2)

= 3 \cdot \frac{1}{2} ln (2)

Simplify

= \frac{3}{2} ln (2)

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What is the integral from 0 to pi/4 of 3tan(x) ?
The integral from 0 to pi/4 of 3tan(x) is 3/2 ln(2)