en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 4 of (2x-4)

Solution

\int_{0}^{4} (2 x - 4) d x

Solution

0

Solution steps

\int_{0}^{4} 2 x - 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} 2 x d x - \int_{0}^{4} 4 d x

\int_{0}^{4} 2 x d x = 16

\int_{0}^{4} 4 d x = 16

= 16 - 16

Simplify

= 0

Graph

Popular Examples

integral from 2 to 3 of (x^3+x)

\int_{2}^{3} (x^{3} + x) d x

integral from x to 0 of e^{-7t}

\int_{x}^{0} e^{- 7 t} d t

integral from 3 to 8 of (7/(x^2)-1)

\int_{3}^{8} (\frac{7}{x ^{2}} - 1) d x

integral from 1 to 9 of-1/9 x+1

\int_{1}^{9} - \frac{1}{9} x + 1 d x

integral from 0 to pi of 2sin(x)cos(x)

\int_{0}^{π} 2 sin (x) cos (x) d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 4 of (2x-4) ?
The integral from 0 to 4 of (2x-4) is 0