What is the integral from-1 to 1 of 3x^4+4x^{5/3} ?

The integral from-1 to 1 of 3x^4+4x^{5/3} is 6/5

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integral from-1 to 1 of 3x^4+4x^{5/3}

\int_{- 1}^{1} 3 x^{4} + 4 x^{\frac{5}{3}} d x

\frac{6}{5}

Decimal

1.2

Solution steps

\int_{- 1}^{1} 3 x^{4} + 4 x^{\frac{5}{3}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} 3 x^{4} d x + \int_{- 1}^{1} 4 x^{\frac{5}{3}} d x

\int_{- 1}^{1} 3 x^{4} d x = \frac{6}{5}

\int_{- 1}^{1} 4 x^{\frac{5}{3}} d x = 0

= \frac{6}{5} + 0

Simplify

= \frac{6}{5}

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\int_{0}^{2} 2 x + x^{2} d x

What is the integral from-1 to 1 of 3x^4+4x^{5/3} ?
The integral from-1 to 1 of 3x^4+4x^{5/3} is 6/5