What is the integral from 1 to 2 of (25x^3+6/(x^2)) ?

The integral from 1 to 2 of (25x^3+6/(x^2)) is 387/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 2 of (25x^3+6/(x^2))

\int_{1}^{2} (25 x^{3} + \frac{6}{x ^{2}}) d x

\frac{387}{4}

Decimal

96.75

Solution steps

\int_{1}^{2} 25 x^{3} + \frac{6}{x ^{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 25 x^{3} d x + \int_{1}^{2} \frac{6}{x ^{2}} d x

\int_{1}^{2} 25 x^{3} d x = \frac{375}{4}

\int_{1}^{2} \frac{6}{x ^{2}} d x = 3

= \frac{375}{4} + 3

Simplify

\frac{375}{4} + 3 : \frac{387}{4}

= \frac{387}{4}

\int_{0.5}^{1} 3 x^{2} d x

\int_{0}^{6} ((2 x) - (x^{2} - 4 x)) d x

\int_{- 1}^{1} (2 x) d x

\int_{0.43}^{x} \frac{1}{( 1 - x ) ^{2}} d x

\int_{x}^{x} cos (t^{2}) d t

What is the integral from 1 to 2 of (25x^3+6/(x^2)) ?
The integral from 1 to 2 of (25x^3+6/(x^2)) is 387/4