What is the integral from-6 to 0 of (5+sqrt(36-x^2)) ?

The integral from-6 to 0 of (5+sqrt(36-x^2)) is 30+9pi

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integral from-6 to 0 of (5+sqrt(36-x^2))

\int_{- 6}^{0} (5 + 36 - x^{2}) d x

30 + 9 π

Decimal

58.27433 \dots

Solution steps

\int_{- 6}^{0} 5 + 36 - x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 6}^{0} 5 d x + \int_{- 6}^{0} 36 - x^{2} d x

\int_{- 6}^{0} 5 d x = 30

\int_{- 6}^{0} 36 - x^{2} d x = 9 π

= 30 + 9 π

\int_{- 5}^{5} ln (x + 6) d x

\int_{- 2}^{0} - 3 x d x

\int_{4}^{6} 6 x^{2} - 7 d x

\int_{1}^{3} 8 x^{3} d x

\int_{0}^{1} (r + 3) (r - 4) d r

What is the integral from-6 to 0 of (5+sqrt(36-x^2)) ?
The integral from-6 to 0 of (5+sqrt(36-x^2)) is 30+9pi