What is the derivative of sin^2(3-6x) ?

The derivative of sin^2(3-6x) is -12sin(3-6x)cos(3-6x)

What is the first derivative of sin^2(3-6x) ?

The first derivative of sin^2(3-6x) is -12sin(3-6x)cos(3-6x)

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derivative of

sin^{2} (3 - 6 x)

- 12 sin (3 - 6 x) cos (3 - 6 x)

Solution steps

\frac{d}{d x} (sin^{2} (3 - 6 x))

Apply the chain rule:

2 sin (3 - 6 x) \frac{d}{d x} (sin (3 - 6 x))

= 2 sin (3 - 6 x) \frac{d}{d x} (sin (3 - 6 x))

\frac{d}{d x} (sin (3 - 6 x)) = - 6 cos (3 - 6 x)

= 2 sin (3 - 6 x) (- 6 cos (3 - 6 x))

Simplify

= - 12 sin (3 - 6 x) cos (3 - 6 x)

n = 1 \sum \infty \frac{n !}{4 ^{n}}

\int (x + 1) x d x

\frac{d}{d x} (\frac{x}{x})

\frac{\partial}{\partial x} (35 e^{5 x} y)

\int x^{\frac{2}{7}} d x

What is the derivative of sin^2(3-6x) ?
The derivative of sin^2(3-6x) is -12sin(3-6x)cos(3-6x)
What is the first derivative of sin^2(3-6x) ?
The first derivative of sin^2(3-6x) is -12sin(3-6x)cos(3-6x)