What is the integral of (sqrt(x)+1)x ?

The integral of (sqrt(x)+1)x is 2/5 x^{5/2}+(x^2)/2+C

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integral of (sqrt(x)+1)x

\int (x + 1) x d x

\frac{2}{5} x^{\frac{5}{2}} + \frac{x ^{2}}{2} + C

Solution steps

\int (x + 1) x d x

Expand

(x + 1) x : x^{\frac{3}{2}} + x

= \int x^{\frac{3}{2}} + x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{\frac{3}{2}} d x + \int x d x

\int x^{\frac{3}{2}} d x = \frac{2}{5} x^{\frac{5}{2}}

\int x d x = \frac{x ^{2}}{2}

= \frac{2}{5} x^{\frac{5}{2}} + \frac{x ^{2}}{2}

Add a constant to the solution

= \frac{2}{5} x^{\frac{5}{2}} + \frac{x ^{2}}{2} + C

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What is the integral of (sqrt(x)+1)x ?
The integral of (sqrt(x)+1)x is 2/5 x^{5/2}+(x^2)/2+C