What is the tangent of x^2-2x,\at x=2 ?

The tangent of x^2-2x,\at x=2 is y=2x-4

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tangent of x^2-2x,\at x=2

tangent of

x^{2} - 2 x, at x = 2

y = 2 x - 4

Solution steps

Find the tangent point:

(2, 0)

Find the slope of

y = x^{2} - 2 x : \frac{d y}{d x} = 2 x - 2

Compute the slope of

y = x^{2} - 2 x

x = 2 : m = 2

Find the line with slope m=

2

and passing through

(2, 0) : y = 2 x - 4

y = 2 x - 4

\int cos (- x) d x

x \to 1 lim (\frac{x - 1}{x ^{2} - x})

\frac{\partial}{\partial y} (2 x^{4} y - 1)

\int (cos (x) + 2 cos (2 x))^{2} d x

f (x) = 10 x sin (x), at x = \frac{π}{2}