What is the integral from-2 to-1 of 1/(sqrt(1+x)) ?

The integral from-2 to-1 of 1/(sqrt(1+x)) is -2i

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integral from-2 to-1 of 1/(sqrt(1+x))

\int_{- 2}^{- 1} \frac{1}{1 + x} d x

- 2 i

Solution steps

\int_{- 2}^{- 1} \frac{1}{1 + x} d x

Apply u-substitution

: \int_{i}^{0} 2 d u

= \int_{i}^{0} 2 d u

Integral of a constant:

\int a d x = a x

= [2 u]_{i}^{0}

Compute the boundaries:

- 2 i

= - 2 i

\int_{0}^{1} (3 x + 1) d x

\int_{0}^{2} 2^{4 x} d x

\int_{0}^{1} t 3^{t^{2}} d t

\int_{0}^{4} (1 + 3 y - y^{2}) d y

\int_{0}^{2} (x e^{x^{2}}) d x

What is the integral from-2 to-1 of 1/(sqrt(1+x)) ?
The integral from-2 to-1 of 1/(sqrt(1+x)) is -2i