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Popular >

integral from-2 to-1 of 1/(x^2)+x

Solution

\int_{- 2}^{- 1} \frac{1}{x ^{2}} + x d x

Solution

- 1

Solution steps

\int_{- 2}^{- 1} \frac{1}{x ^{2}} + x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{- 1} \frac{1}{x ^{2}} d x + \int_{- 2}^{- 1} x d x

\int_{- 2}^{- 1} \frac{1}{x ^{2}} d x = \frac{1}{2}

\int_{- 2}^{- 1} x d x = - \frac{3}{2}

= \frac{1}{2} - \frac{3}{2}

Simplify

\frac{1}{2} - \frac{3}{2} : - 1

= - 1

Graph

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Frequently Asked Questions (FAQ)

What is the integral from-2 to-1 of 1/(x^2)+x ?
The integral from-2 to-1 of 1/(x^2)+x is -1