What is the integral from 0 to 2 of (2x^2-3x) ?

The integral from 0 to 2 of (2x^2-3x) is -2/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 2 of (2x^2-3x)

\int_{0}^{2} (2 x^{2} - 3 x) d x

- \frac{2}{3}

Decimal

- 0.66666 \dots

Solution steps

\int_{0}^{2} 2 x^{2} - 3 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} 2 x^{2} d x - \int_{0}^{2} 3 x d x

\int_{0}^{2} 2 x^{2} d x = \frac{16}{3}

\int_{0}^{2} 3 x d x = 6

= \frac{16}{3} - 6

Simplify

\frac{16}{3} - 6 : - \frac{2}{3}

= - \frac{2}{3}

\int_{x}^{0} e^{- 8 t} d t

\int_{1}^{9} 7 x d x

\int_{1}^{\infty} \frac{1}{2 ^{n}}

\int_{0}^{1} - 2 x^{2} d x

\int_{0}^{1} x (x^{2} + 2) d x

What is the integral from 0 to 2 of (2x^2-3x) ?
The integral from 0 to 2 of (2x^2-3x) is -2/3