What is the integral from 1 to 3 of (6/x) ?

The integral from 1 to 3 of (6/x) is 6ln(3)

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integral from 1 to 3 of (6/x)

\int_{1}^{3} (\frac{6}{x}) d x

6 ln (3)

Decimal

6.59167 \dots

Solution steps

\int_{1}^{3} \frac{6}{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int_{1}^{3} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= 6 [ln ∣ x ∣]_{1}^{3}

Compute the boundaries:

ln (3)

= 6 ln (3)

\int_{x^{2}}^{1} y d y

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\int_{- 2}^{- 1} 4 - x^{2} d x

What is the integral from 1 to 3 of (6/x) ?
The integral from 1 to 3 of (6/x) is 6ln(3)