What is the integral from 0 to 9 of sqrt(8t) ?

The integral from 0 to 9 of sqrt(8t) is 36sqrt(2)

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integral from 0 to 9 of sqrt(8t)

\int_{0}^{9} 8 t d t

362

Decimal

50.91168 \dots

Solution steps

\int_{0}^{9} 8 t d t

Simplify

8 t : 22 t

= \int_{0}^{9} 22 t d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 22 \cdot \int_{0}^{9} t d t

Apply the Power Rule

: [\frac{2}{3} t^{\frac{3}{2}}]_{0}^{9}

= 22 [\frac{2}{3} t^{\frac{3}{2}}]_{0}^{9}

Compute the boundaries:

18

= 22 \cdot 18

Simplify

= 362

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What is the integral from 0 to 9 of sqrt(8t) ?
The integral from 0 to 9 of sqrt(8t) is 36sqrt(2)