What is the integral from 0 to sqrt((4-x^2) of)y ?

The integral from 0 to sqrt((4-x^2) of)y is (-x^2+4)/2

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integral from 0 to sqrt((4-x^2) of)y

\int_{0}^{(4 - x^{2})} y d y

\frac{- x ^{2} + 4}{2}

Solution steps

\int_{0}^{4 - x^{2}} y d y

Apply the Power Rule

: [\frac{y ^{2}}{2}]_{0}^{4 - x^{2}}

= [\frac{y ^{2}}{2}]_{0}^{4 - x^{2}}

Compute the boundaries:

\frac{- x ^{2} + 4}{2}

= \frac{- x ^{2} + 4}{2}

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What is the integral from 0 to sqrt((4-x^2) of)y ?
The integral from 0 to sqrt((4-x^2) of)y is (-x^2+4)/2