What is the integral from 0 to 3 of (4x) ?

The integral from 0 to 3 of (4x) is 18

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 3 of (4x)

\int_{0}^{3} (4 x) d x

18

Solution steps

\int_{0}^{3} 4 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int_{0}^{3} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{3}

= 4 [\frac{x ^{2}}{2}]_{0}^{3}

Compute the boundaries:

\frac{9}{2}

= 4 \cdot \frac{9}{2}

Simplify

= 18

\int_{0}^{1} x \cdot 1 + 4 x^{2} d x

\int_{0}^{2} (3 x^{2} + 2 x + 1) d x

\int_{0}^{b} \frac{1}{x} d x

\int_{1}^{5} \frac{8}{x ^{3}} d x

\int_{0}^{x} cos (x^{2}) d x

What is the integral from 0 to 3 of (4x) ?
The integral from 0 to 3 of (4x) is 18