What is the integral from 2 to 9 of \sqrt[3]{x-1} ?

The integral from 2 to 9 of \sqrt[3]{x-1} is 45/4

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integral from 2 to 9 of \sqrt[3]{x-1}

\int_{2}^{9} 3 x - 1 d x

\frac{45}{4}

Decimal

11.25

Solution steps

\int_{2}^{9} 3 x - 1 d x

Apply u-substitution

: \int_{1}^{8} 3 u d u

= \int_{1}^{8} 3 u d u

Apply the Power Rule

: [\frac{3}{4} u^{\frac{4}{3}}]_{1}^{8}

= [\frac{3}{4} u^{\frac{4}{3}}]_{1}^{8}

Compute the boundaries:

\frac{45}{4}

= \frac{45}{4}

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What is the integral from 2 to 9 of \sqrt[3]{x-1} ?
The integral from 2 to 9 of \sqrt[3]{x-1} is 45/4