What is the integral from 1 to infinity of e^{-ax} ?

The integral from 1 to infinity of e^{-ax} is (e^{-a})/a

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integral from 1 to infinity of e^{-ax}

\int_{1}^{\infty} e^{- a x} d x

\frac{e ^{- a}}{a}

Solution steps

\int_{1}^{\infty} e^{- a x} d x

Compute the indefinite integral:

\int e^{- a x} d x = - \frac{1}{a} e^{- a x} + C

Compute the boundaries:

\int_{1}^{\infty} e^{- a x} d x = 0 - (- e^{- a} \frac{1}{a})

= 0 - (- e^{- a} \frac{1}{a})

Simplify

= \frac{e ^{- a}}{a}

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What is the integral from 1 to infinity of e^{-ax} ?
The integral from 1 to infinity of e^{-ax} is (e^{-a})/a