What is the integral from 1 to 16 of (x^{-3/4}) ?

The integral from 1 to 16 of (x^{-3/4}) is 4

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integral from 1 to 16 of (x^{-3/4})

\int_{1}^{16} (x^{- \frac{3}{4}}) d x

4

Solution steps

\int_{1}^{16} x^{- \frac{3}{4}} d x

Apply the Power Rule

: [4 x^{\frac{1}{4}}]_{1}^{16}

= [4 x^{\frac{1}{4}}]_{1}^{16}

Compute the boundaries:

4

= 4

\int_{- 2}^{3} (x^{2} - 2 x + 1) d x

\int_{0}^{\frac{5 π}{6}} 4 tan (\frac{x}{5}) d x

\int_{1}^{9} \frac{x - 4}{x} d x

\int_{0}^{2} \frac{16}{x ^{2} + 4} d x

\int_{0}^{7} 4 x d x

What is the integral from 1 to 16 of (x^{-3/4}) ?
The integral from 1 to 16 of (x^{-3/4}) is 4