What is the integral from-1 to 1 of (x^3)/(x^2+1) ?

The integral from-1 to 1 of (x^3)/(x^2+1) is 0

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integral from-1 to 1 of (x^3)/(x^2+1)

\int_{- 1}^{1} \frac{x ^{3}}{x ^{2} + 1} d x

0

Solution steps

\int_{- 1}^{1} \frac{x ^{3}}{x ^{2} + 1} d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

\frac{x ^{3}}{x ^{2} + 1} :

Odd

= 0

\int_{0}^{0.4} 2 (1 - x) d x

\int_{- 1}^{1} \frac{1}{4} x (2 x + 2) d x

\int_{- 2}^{2} x^{2} - 2 x + 2 d x

\int_{0}^{2} ∣ sin (x) ∣ d x

\int_{0}^{r} 1 d r

What is the integral from-1 to 1 of (x^3)/(x^2+1) ?
The integral from-1 to 1 of (x^3)/(x^2+1) is 0