What is the integral from 0 to 0.4 of 2(1-x) ?

The integral from 0 to 0.4 of 2(1-x) is 0.64

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integral from 0 to 0.4 of 2(1-x)

\int_{0}^{0.4} 2 (1 - x) d x

0.64

Solution steps

\int_{0}^{0.4} 2 (1 - x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{0}^{0.4} 1 - x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 2 (\int_{0}^{0.4} 1 d x - \int_{0}^{0.4} x d x)

\int_{0}^{0.4} 1 d x = 0.4

\int_{0}^{0.4} x d x = 0.08

= 2 (0.4 - 0.08)

Simplify

= 0.64

\int_{- 1}^{1} \frac{1}{4} x (2 x + 2) d x

\int_{- 2}^{2} x^{2} - 2 x + 2 d x

\int_{0}^{2} ∣ sin (x) ∣ d x

\int_{0}^{r} 1 d r

\int_{- 1}^{2} \frac{1}{3} x^{2} d x

What is the integral from 0 to 0.4 of 2(1-x) ?
The integral from 0 to 0.4 of 2(1-x) is 0.64