What is the integral from 0 to 1 of-4x ?

The integral from 0 to 1 of-4x is -2

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integral from 0 to 1 of-4x

\int_{0}^{1} - 4 x d x

- 2

Solution steps

\int_{0}^{1} - 4 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 4 \cdot \int_{0}^{1} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{1}

= - 4 [\frac{x ^{2}}{2}]_{0}^{1}

Compute the boundaries:

\frac{1}{2}

= - 4 \cdot \frac{1}{2}

Simplify

= - 2

\int_{0}^{2 y} 1 d x

\int_{2}^{B} (2 x - 3)^{3} d x

\int_{3}^{6} \frac{6}{2 x - 3} d x

\int_{4}^{7} 28 - 11 x + x^{2} d x