What is the integral from-1 to 1 of x/(sqrt(2+x^2)) ?

The integral from-1 to 1 of x/(sqrt(2+x^2)) is 0

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integral from-1 to 1 of x/(sqrt(2+x^2))

\int_{- 1}^{1} \frac{x}{2 + x ^{2}} d x

0

Solution steps

\int_{- 1}^{1} \frac{x}{2 + x ^{2}} d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

\frac{x}{2 + x ^{2}} :

Odd

= 0

\int_{- 7}^{1} (- x^{2} - 3 x) d x

\int_{0}^{\frac{1}{2}} \frac{1}{x ( ln ( x ) ) ^{2}} d x

\int_{0}^{5} x^{2} + 4 d x

\int_{0}^{\frac{π}{3}} (cos (x) + 1) d x

\int_{3}^{4} f (2^{x}) 2^{x} d x

What is the integral from-1 to 1 of x/(sqrt(2+x^2)) ?
The integral from-1 to 1 of x/(sqrt(2+x^2)) is 0