What is the integral from-i to i of 1/z ?

The integral from-i to i of 1/z is 0

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integral from-i to i of 1/z

\int_{- i}^{i} \frac{1}{z} d z

0

Solution steps

\int_{- i}^{i} \frac{1}{z} d z

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

\frac{1}{z} :

Odd

= 0

\int_{0}^{π} 2 + x^{2} d x

\int_{0}^{2 π} \frac{1}{3} d θ

\int_{- 3}^{3} \frac{6 e ^{- 6 x} - 6 e ^{6 x}}{( e ^{- 6 x} + e ^{6 x} ) ^{2}} d x

\int_{- 1}^{x^{2}} (1 + x^{3})^{4} d x

\int_{0}^{1} π