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Popular >

integral from 0 to 3 of (5t-9)

Solution

\int_{0}^{3} (5 t - 9) d t

Solution

- \frac{9}{2}

+1

Decimal

- 4.5

Solution steps

\int_{0}^{3} 5 t - 9 d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{3} 5 t d t - \int_{0}^{3} 9 d t

\int_{0}^{3} 5 t d t = \frac{45}{2}

\int_{0}^{3} 9 d t = 27

= \frac{45}{2} - 27

Simplify

\frac{45}{2} - 27 : - \frac{9}{2}

= - \frac{9}{2}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 3 of (5t-9) ?
The integral from 0 to 3 of (5t-9) is -9/2