What is the integral from 0 to t of sin(a) ?

The integral from 0 to t of sin(a) is -cos(t)+1

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integral from 0 to t of sin(a)

\int_{0}^{t} sin (a) d a

- cos (t) + 1

Solution steps

\int_{0}^{t} sin (a) d a

Use the common integral:

\int sin (a) d a = - cos (a)

= [- cos (a)]_{0}^{t}

Compute the boundaries:

- cos (t) + 1

= - cos (t) + 1

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What is the integral from 0 to t of sin(a) ?
The integral from 0 to t of sin(a) is -cos(t)+1