What is the integral from 0 to 3 of (1/x)^2 ?

The integral from 0 to 3 of (1/x)^2 is diverges

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integral from 0 to 3 of (1/x)^2

\int_{0}^{3} (\frac{1}{x})^{2} d x

diverges

Solution steps

\int_{0}^{3} (\frac{1}{x})^{2} d x

Simplify

(\frac{1}{x})^{2} : \frac{1}{x ^{2}}

= \int_{0}^{3} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{0}^{3}

= [- \frac{1}{x}]_{0}^{3}

Compute the boundaries:

diverges

= diverges

\int_{- 3}^{5} ∣ x + 1 ∣ d x

\int_{0}^{3} (2) d x

\int_{0}^{1} \frac{x}{1 + 2 x ^{2}} d x

\int_{2}^{4} f (t) d t

\int_{0}^{x} \frac{t}{t + 5} d t

What is the integral from 0 to 3 of (1/x)^2 ?
The integral from 0 to 3 of (1/x)^2 is diverges