What is the integral from 0 to 1 of 9x^3 ?

The integral from 0 to 1 of 9x^3 is 9/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 1 of 9x^3

\int_{0}^{1} 9 x^{3} d x

\frac{9}{4}

Decimal

2.25

Solution steps

\int_{0}^{1} 9 x^{3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \int_{0}^{1} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{0}^{1}

= 9 [\frac{x ^{4}}{4}]_{0}^{1}

Compute the boundaries:

\frac{1}{4}

= 9 \cdot \frac{1}{4}

Simplify

= \frac{9}{4}

\int_{2}^{0} 3 x (2 - x) d x

\int_{2}^{3} - \frac{4}{x ^{2}} d x

\int_{0}^{1} 1 5^{2 x} d x

\int_{0}^{1} x^{2} 9 - x^{3} d x

\int_{0}^{1} (x^{6} + 1) d x

What is the integral from 0 to 1 of 9x^3 ?
The integral from 0 to 1 of 9x^3 is 9/4