What is the integral from 1 to 3 of y^2 ?

The integral from 1 to 3 of y^2 is 26/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 3 of y^2

\int_{1}^{3} y^{2} d y

\frac{26}{3}

Decimal

8.66666 \dots

Solution steps

\int_{1}^{3} y^{2} d y

Apply the Power Rule

: [\frac{y ^{3}}{3}]_{1}^{3}

= [\frac{y ^{3}}{3}]_{1}^{3}

Compute the boundaries:

\frac{26}{3}

= \frac{26}{3}

\int_{1}^{2} (2 x + \frac{2}{x ^{2}}) d x

\int_{0}^{1} 7 + 4 t^{2} d t

\int_{0}^{2} y (2 y^{2} - \frac{y ^{2}}{2}) d y

\int_{4}^{5} x^{2} + 2 x + 2 d x

\int_{0}^{50} \frac{t}{w - 20} d t

What is the integral from 1 to 3 of y^2 ?
The integral from 1 to 3 of y^2 is 26/3