What is the integral from 0 to 0.5 of x^3 ?

The integral from 0 to 0.5 of x^3 is 0.015625

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 0.5 of x^3

\int_{0}^{0.5} x^{3} d x

0.015625

Solution steps

\int_{0}^{0.5} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{0}^{0.5}

= [\frac{x ^{4}}{4}]_{0}^{0.5}

Simplify

= [0.25 x^{4}]_{0}^{0.5}

Compute the boundaries:

0.015625

= 0.015625

\int_{0}^{1} \frac{1}{x ^{2} + 2 x + 2} d x

\int_{0}^{1} (7 x^{2} - 6 x + 3) d x

\int_{1}^{9} t d t

\int_{0}^{π} - 4 sin (x) d x

\int_{- 6}^{- 2} (- x + 3) d x

What is the integral from 0 to 0.5 of x^3 ?
The integral from 0 to 0.5 of x^3 is 0.015625