What is the integral from 0 to 1 of (x^4) ?

The integral from 0 to 1 of (x^4) is 1/5

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integral from 0 to 1 of (x^4)

\int_{0}^{1} (x^{4}) d x

\frac{1}{5}

Decimal

0.2

Solution steps

\int_{0}^{1} x^{4} d x

Apply the Power Rule

: [\frac{x ^{5}}{5}]_{0}^{1}

= [\frac{x ^{5}}{5}]_{0}^{1}

Compute the boundaries:

\frac{1}{5}

= \frac{1}{5}

\int_{- 1}^{1} x \cdot x^{2} d x

\int_{- 3}^{3} 12 - x^{2} - x^{2} - 6 d x

\int_{\frac{8}{27}}^{1} \frac{( 28 x ^{\frac{4}{3}} - 26 x ^{\frac{1}{3}} )}{x ^{2}} d x

\int_{0}^{12} ∣ x - 6 ∣ d x

\int_{- 4}^{0} x^{3} + x^{2} - 6 x - 6 x d x

What is the integral from 0 to 1 of (x^4) ?
The integral from 0 to 1 of (x^4) is 1/5