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Popular >

integral from-1 to 1 of (4-9x)

Solution

\int_{- 1}^{1} (4 - 9 x) d x

Solution

8

Solution steps

\int_{- 1}^{1} 4 - 9 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} 4 d x - \int_{- 1}^{1} 9 x d x

\int_{- 1}^{1} 4 d x = 8

\int_{- 1}^{1} 9 x d x = 0

= 8 - 0

Simplify

= 8

Graph

Popular Examples

integral from 0 to pi of xcos(ax)

\int_{0}^{π} x cos (a x) d x

integral from 1 to 3 of 1/9 x^2

\int_{1}^{3} \frac{1}{9} x^{2} d x

integral from θ to x of e^{-(x-θ)}

\int_{θ}^{x} e^{- (x - θ)} d x

integral from 0 to 1 of (arccos(x))^2

\int_{0}^{1} (arccos (x))^{2} d x

integral from-2 to 4 of (2x-1)

\int_{- 2}^{4} (2 x - 1) d x

Frequently Asked Questions (FAQ)

What is the integral from-1 to 1 of (4-9x) ?
The integral from-1 to 1 of (4-9x) is 8