What is the integral from 3 to 5 of 6/(x^2) ?

The integral from 3 to 5 of 6/(x^2) is 4/5

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integral from 3 to 5 of 6/(x^2)

\int_{3}^{5} \frac{6}{x ^{2}} d x

\frac{4}{5}

Decimal

0.8

Solution steps

\int_{3}^{5} \frac{6}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int_{3}^{5} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{3}^{5}

= 6 [- \frac{1}{x}]_{3}^{5}

Compute the boundaries:

\frac{2}{15}

= 6 \cdot \frac{2}{15}

Simplify

= \frac{4}{5}

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What is the integral from 3 to 5 of 6/(x^2) ?
The integral from 3 to 5 of 6/(x^2) is 4/5