What is the integral from 5 to 10 of-0.6x^2+4x+4 ?

The integral from 5 to 10 of-0.6x^2+4x+4 is -5

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integral from 5 to 10 of-0.6x^2+4x+4

\int_{5}^{10} - 0.6 x^{2} + 4 x + 4 d x

- 5

Solution steps

\int_{5}^{10} - 0.6 x^{2} + 4 x + 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{5}^{10} 0.6 x^{2} d x + \int_{5}^{10} 4 x d x + \int_{5}^{10} 4 d x

\int_{5}^{10} 0.6 x^{2} d x = 175

\int_{5}^{10} 4 x d x = 150

\int_{5}^{10} 4 d x = 20

= - 175 + 150 + 20

Simplify

= - 5

\int_{- 1}^{1} x (x^{2} + 5 x)^{3} d x

\int_{1}^{9} 4 u d u

\int_{0}^{π} 5 x cos (x) d x

\int_{1}^{4} π (ln (x))^{2} d x

\int_{n}^{n + 1} \frac{cos ( x )}{x} d x

What is the integral from 5 to 10 of-0.6x^2+4x+4 ?
The integral from 5 to 10 of-0.6x^2+4x+4 is -5