What is the integral from 0 to 6 of pi(sqrt(x))^2 ?

The integral from 0 to 6 of pi(sqrt(x))^2 is pi18

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integral from 0 to 6 of pi(sqrt(x))^2

\int_{0}^{6} π (x)^{2} d x

π 18

Decimal Notation

56.54866 \dots

Solution steps

\int_{0}^{6} π (x)^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= π \cdot \int_{0}^{6} (x)^{2} d x

Simplify

(x)^{2} : x

= π \cdot \int_{0}^{6} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{6}

= π [\frac{x ^{2}}{2}]_{0}^{6}

Compute the boundaries:

18

= π 18

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What is the integral from 0 to 6 of pi(sqrt(x))^2 ?
The integral from 0 to 6 of pi(sqrt(x))^2 is pi18